X^2+156x+156=0

Solution for X^2+156x+156=0 equation:

X^2+156X+156=0

a = 1; b = 156; c = +156;
Δ = b2-4ac
Δ = 1562-4·1·156
Δ = 23712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23712}=\sqrt{16*1482}=\sqrt{16}*\sqrt{1482}=4\sqrt{1482}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(156)-4\sqrt{1482}}{2*1}=\frac{-156-4\sqrt{1482}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(156)+4\sqrt{1482}}{2*1}=\frac{-156+4\sqrt{1482}}{2}
$